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In The Given Figure From A Point P Two Tangents Pt And Ps Are Drawn To A Circle With Centre O

in The Given Figure From A Point P Two Tangents Pt And Ps Are Drawn To A Circle With Centre O
in The Given Figure From A Point P Two Tangents Pt And Ps Are Drawn To A Circle With Centre O

In The Given Figure From A Point P Two Tangents Pt And Ps Are Drawn To A Circle With Centre O It is given that ps and pt are tangents to the circle with centre o. also, ∠spt = 120°. to prove: op = 2ps. proof: in pto and pso, pt = ps (tangents drawn from an external point to a circle are equal in length.) to = so (radii of the circle) ∠pto = ∠pso = 90° \(\therefore \triangle pto \cong\triangle pso\) (by sas congruency) thus,. In the given figure, p a and p b are two tangents drawn from an external point p to a circle with centre o. prove that o p is the right bisector of line segment a b . view solution.

In The figure From An External point p two tangents pt and Ps
In The figure From An External point p two tangents pt and Ps

In The Figure From An External Point P Two Tangents Pt And Ps In the given diagram, o is the centre of the circle. pr and pt are two tangents drawn from the external point p and touching the circle at q and s respectively. mn is a diameter of the circle. given ∠pqm = 42° and ∠psm = 25°. find: ∠oqm; ∠qns; ∠qos; ∠qms. Given, in the given figure from a point p, two tangents pt and ps are drawn to a circle with centre o such that ∠spt = 120° to find, prove that op = 2ps. solution, consider Δops and Δopt. os = ot ( radii) ∠osp = ∠otp = 90 (tangents are perpendicular to the radii) sp = st ( tangents to a circle from the external point are congruence). Very short answer type questions [1 mark] question 1. from an external point p, tangents pa and pb are drawn to a circle with centre o. if ∠pab = 50°, then find ∠aob. solution: question 2. in given figure, pq is a tangent at a point c to a circle with centre o. if ab is a diameter and ∠cab = 30°, find ∠pca. Q.8: in the figure, from an external point p, two tangents pt and ps are drawn to a circle with centre o and radius r. if op = 2r, show that ∠ots = ∠ost = 30°. solution: given that from an external point p, two tangents pt and ps are drawn to a circle with center o and radius r and op = 2r. os = ot {radii of same circle}.

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